Question 973650
I am trying to figure out a system of equations problem: 
-2x=-10y-2
-x=8y=5 
Here's what I did: 
I chose to use the top equation: 
-2x=-10y-2
+2 +2 
-2x+2= -10y
/10 /10 
Y= -2/10X + 2/10   HERE IS WHERE YOU WENT WRONG.  YOU HAD TO DIVIDE EVERYTHING BY -10, not 10, and the 2 had to be divided as well..

-2x=-10y-2
-x=8y=5    This needs to be clearer.  There shouldn't be two equal signs.  

The first becomes -2x+2=-10y; divide by -10   (1/5)x+(-1/5)=y

-x=8y+5  ?   -x=(8/5)x-(8/5)+5;;;  -x=(8/5)x +(17/5)

(-13/5) x=(17/5)
x=-(17/13)

OR, is it 
-x=8y-5?    then it will be (33/13)

OR, is it
-x+8y=5?   then it is -x + (8/5)x-(8/5)=(25/5)
(3/5)x=(33/5)
x=11

-22=-10y-2
y=2

Hope that helps.  If it doesn't, then rewrite the second equation and resubmit.