Question 973592
Find three consecutive largest positive integers such that the sum of one third of first ,one fourth of second and one fifth of third is at most 20.
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1st: x-1
2nd: x
3rd: x+1
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Equation::
(1/3)(x-1) + (1/4)x + (1/5)(x+1) <= 20
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Multiply thru by 60 to get:
20x-20 + 15x + 12x + 12 <= 20
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47x <= 28
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x <= 28/47
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Comment:: x-1 cannot be a positive integer.
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Please check the problem statement.
Cheers,
Stan H.
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