Question 973463
a) log5(4) + log5(2)
=log5(4*2)
=log5(8)
You might add = log(8)/log(5)
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b) 9 log3(9) + log3(81)^2
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9 = 3^2, 81 = 3^4
= {{{log(3,9^9) + log(3,3^8)}}}
= {{{log(3,3^18) + log(3,3^8)}}}
= {{{log(3,3^26)}}}
= {{{26*log(3,3)}}}
= 26
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=9 log3(9*81)^2
=9log3(729)^2
=9log3(531441)^2
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531441 = 3^12
= 9log(3,3^24)
= log(3,3^26)
= 26