Question 973431
.
Is TT supposed to be pi?
C=circumference; r=radius; A=area
{{{C=(pi)2r}}}
{{{C/(2(pi))=r}}}
{{{12(pi)/(2(pi))=r}}}
{{{6=r}}}
.
{{{A=(pi)r^2}}}
{{{A=(pi)6^2}}}
{{{A=36(pi)units^2}}}