Question 973434
mean=630  sd=50
The first is 50%

z= (value-mean)/sd
But value=mean, so z=0, and that is at the midpoint of the probability curve.

z=(693-630)/50  ;; 10% over the mean demand is 10%of 630 (63) added to 630.
z=63/50= +1.26
The probability wanted is that of z>1.26  This is relatively small, and in fact it is 0.104