Question 82745
what expression raised to the forth power is 81x^12y^8z^16?
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Wouldn't it be: {{{(81x^12*y^8*z^16)^(1/4)}}}?
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Using the rules of exponents:
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{{{81^(1/4)}}} = 3
{{{(x^12)^(1/4)}}} = {{{x^3}}}
{{{(y^8)^(1/4)}}} = {{{y^2}}}
{{{(z^16)^(1/4)}}} = {{{z^4}}}
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So you have: {{{(3x^3*y^2*z^4)}}}
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Check: {{{(3x^3*y^2*z^4)^4}}} = {{{81x^12*y^8*z^16}}}
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