Question 973397
Find the value of the trigonometric function sin (t) if sec t=-4/3 and the terminal side of angle t lies in quadrant II
------------
cos = 1/sec = -3/4
{{{sin(t) = sqrt(1 - cos^2(t)) = sqrt(7)/4}}}
sine is + in Q2
{{{sin(t) = sqrt(7)/4}}}