Question 973342
{{{3x-2y+3x+2y=6+18}}}
{{{6x=24}}}
{{{x=4}}}


{{{2y=18-3x}}}
{{{y=(18-3x)/2}}}
{{{y=(18-3*4)/2}}}
{{{y=6/2}}}
{{{y=3}}}


The two equations intersect at (4,3).


Distance Formula or Pythagorean Theorem give distance from Origin,
{{{sqrt(4^2+3^2)=sqrt(16+9)=highlight(5)}}}.