Question 973280
Find the equation of the line that passes through the point (12,6) with a slope of - 3/4

Could you send the solution.
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y-y1 = m*(x-x1) where (x1,y1) is the point and m is the slope
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y-6 = (-3/4)*(x-12)
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It's not "the equation" it's an equation of the line.  There are others.