<PRE><B>Question 973236</B>
2x-3/x+4 = x-3/x-4
Multiply the whole equation by (x-4) (x+4).   OR  Cross-multiply.

(2x-3) (x-4) = (x-3) (x+4)  One of the two terms you are multiplying by cancels the denominator.

Now distribute.

2x^2-11x+12= x^2+x-12

x^2 -12x +24=0
(1/2) [12 +/- sqrt (144-96)]

(1/2) [12 +/- 4 sqrt (3)]

6+ 2sqrt (3)     = 9.464
6-2 sqrt (3)

Substitute the numerical value in

(15.928/13.464) = 6.464/5.464

1.1830  ;  1.1830

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