Question 973243
r = worth of red chip
b = worth of blue chip


3r + 4b = 23   {3 red chips and 4 blue chips for $23}
5r + 12b = 65   {5 red chips and 12 blue chips for $65}


-9r - 12b = -69   {multiplied top equation by -3}
5r + 12b = 65   {bottom equation stays the same}
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-4r = -4 {added the two equations}
r = 1   {divided each side by -4}


3r + 4b = 23 {top equation}
3(1) + 4b = 23 {substituted 1 for r into top equation}
3 + 4b = 23 {multiplied}
4b = 20 {subtracted 3 from each side}
b = 5 {divided each side by 4}


red chip is worth $1
blue chip is worth $5
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