Question 973215
How do you find the equation of a circle if it lies in the first quadrant and is tangent to x=-3 y=3 and x=11
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Tangent to x=-3 and x=11 makes the diameter 14 --> r = 7
and the center is (4,y)
7 units from y=3 --> y = -4 or y = 10
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In Q1 --> y = 10
--> center at (4,10)
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{{{(x-4)^2 + (y-10)^2 = 49}}} is the circle