Question 973197
If 6 times number of permutation of n items taken 3 at a time is equal to 7 times
no of permutation ( n-1) item taken 3 at a time then n value is?
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6∙(nP3) = 7∙[(n-1)P3]

{{{6*(n*(n-1)*(n-2)^"")}}}{{{""=""}}}{{{7*((n-1)*(n-2)*(n-3)^"")}}}

{{{6*(n*cross((n-1)*(n-2))^"")}}}{{{""=""}}}{{{7*(cross((n-1)*(n-2))*(n-3)^"")}}}

{{{6*n}}}{{{""=""}}}{{{7*(n-3)}}}

{{{6*n}}}{{{""=""}}}{{{7*n-21}}}

{{{-n}}}{{{""=""}}}{{{-21}}}

{{{n}}}{{{""=""}}}{{{21}}}

Edwin</pre>