Question 973084
2x²-4x+2 = 0
<pre>
Divide every number by 2:

{{{expr(2/2)x^2-expr(4/2)x+2/2}}}{{{""=""}}}{{{0/2}}}

x²-2x+1 = 0

Factor the left side:

(x-1)(x-1) = 0

Use the zero-factor property:

x-1 = 0; x-1 = 0
  x = 1;   x = 1

They are both the same, so there is just one real-number solution.

That solution is x = 1.

Edwin</pre>