Question 973156
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Let *[tex \Large x] represent the value of the measure of the two equal measure angles.  Then the third angle must measure *[tex \Large 2x].  The sum of the first three angles is then *[tex \Large 4x], twice this sum is *[tex \Large 8x], and then the fourth angle must measure *[tex \Large 8x\ -\ 60]


The sum of all the angles is then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ +\ (8x\ -\ 60)]


And this sum must equal 360 because this is a quadrilateral, hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ +\ 8x\ -\ 60\ =\ 360]


Solve for *[tex \Large x], *[tex \Large 2x], and *[tex \Large 8x\ -\ 60]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \