Question 973113
9x^2-22x+8=0   Multiply the 8 by the leading coefficient, and rewrite leading coefficient as 1.

x^2-22x+72=0;  factor into (x-18)(x-4)=0   divide now by the 9 you multiplied by, reducing all fractions.
(x-(18/9)) (x-(4/9))=0

(x-2) (9x-4)=0 are factors.  They multiply out to the original polynomial.

The quadratic formula also works
(1/18) [22 +/- sqrt (484- 288)]= (1/18) [22 +/- sqrt (196)]

(1/18) (22+14) ;  (1/18) (22-14)
roots are 2 and 4/9, same as above.

will take smaller zero to be alpha (4/9)  
(4/9)^4=  (256/6561)
2^4=16
16.0390

{{{graph (300,300,-3,3,-10,10,9x^2-22x+8)}}}