Question 973066
Retention is  {{{100-5.25=94.75}}} percent each hour.


Starting with quantity 1, Using the model,
{{{0.9475=1*e^(k*1)}}}
{{{0.9475=e^k}}}
{{{ln(0.9475)=k*1}}}
{{{highlight(k=ln(0.9475))}}} and the model is more specifically {{{highlight_green(A(t)=A*e^(-0.05393t))}}}.



HALF-LIFE

{{{(1/2)=1*e^(-0.05393t)}}}


{{{ln(1/2)=-0.05393*t*ln(e)}}}


{{{t=ln(1/2)/(-0.05393)}}}


{{{highlight(t=12.9)}}} hours