Question 973037
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Set equation=0
{{{x^3(4e^(4x))+3x^2*e^(4x)=0}}} factor out {{{x^2e^(4x)}}}
{{{(x^2e^(4x))(4x+3)=0}}}
{{{x^2e^(4x)=0}}} {{{or}}} {{{4x+3=0}}}
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Since {{{e^(4x))}}} is not zero (a number other than 0 raised to a power cannot equal 0), the first equation changes to x^2=0.
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{{{x^2=0}}} {{{or}}} {{{4x+3=0}}}
{{{ x=0}}} {{{or}}} {{{x=-3/4}}}