Question 82870
Here, you simply substitute the value given for x into the expression of f(x).
{{{f(x)=-x^3+3x^2-x+4}}}
{{{f(-2)=-(-2)^3+3(-2)^2-(-2)+4=26}}}
{{{f(0)=-(0)^3+3(0)^2-(0)+4=4}}}
{{{f(3)=-(3)^3+3(3)^2-(3)+4=1}}}