Question 972954

let's numbers be {{{x}}} and {{{y}}}

if the sum of two numbers is {{{89}}}, then we have

{{{x+y=89}}}.........eq.1


if adding four times the first number (means {{{4x}}}) to the second number gives {{{155}}}, we have

{{{4x+y=155}}}.........eq.2

now we have system to solve:

{{{x+y=89}}}.........eq.1
{{{4x+y=155}}}.........eq.2
---------------------------subtract eq.1 from eq.2

{{{4x+y-x-y=155-89}}}

{{{4x+cross(y)-x-cross(y)=66}}}

{{{4x-x=66}}}

{{{3x=66}}}

{{{x=66/3}}}

{{{highlight(x=22)}}}


now go to eq.1, substitute {{{22}}} for {{{x}}} and solve for {{{y}}}

{{{22+y=89}}}.........eq.1

{{{y=89-22}}}

{{{highlight(y=67)}}}


so, your numbers are {{{22}}} and {{{67}}}