Question 972875
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Sorry, I'm not going to tell you the answer, but I will show you how to calculate it for yourself.


*[tex \LARGE {{n}\choose{k}}] is the number of combinations of *[tex \Large n] things taken *[tex \Large k] at a time and is calculated by *[tex \Large \frac{n!}{k!(n\,-\,k)!}]


You have *[tex \LARGE {{6}\choose{4}}] ways to choose the students and for each of these choices you have *[tex \LARGE {{5}\choose{3}}] to choose the teachers.  So your total is the product of these two values.  Do the arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

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