Question 972862
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ P\left(1\ +\ \frac{r}{n}\right)^{nt}]


Where *[tex \Large A] is the future value, *[tex \Large P] is the present value, *[tex \Large r] is the interest rate expressed as a decimal, *[tex \Large n] is the number of compounding periods per year, and *[tex \Large t] is the number of years]


For this problem *[tex \Large P\ =\ 1000], *[tex \Large r\ =\ 0.07], *[tex \Large n\ =\ 1], and *[tex \Large t\ =\ 10].  You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \