Question 972847
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Secant-Tangent Rule.  The whole secant times the external part of the secant is equal to the tangent squared


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ mAD\,\cdot\,mAC\ =\ (mAB)^2]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ k\ =\ \sqrt{44}]


You can do your own calculator work.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \