Question 972785
{{{x/9+y/3=2x-3y+3=0}}}


{{{system(x+3y=0,2x-3y=-3)}}}
{{{(x+3y)+(2x-3y)=0+(-3)}}}
{{{3x=-3}}}
{{{highlight(x=-1)}}}


From the first equation,
{{{3y=-x}}}
{{{y=-x/3}}}
substitute for x,
{{{highlight(y=1/3)}}}