Question 972687
2i(4+5i)(4−5i)/4+i

2i(16-25i^2)/(4+i)
2i(41)/4+i
82i/(4+i)

Note, there was no divisor placed.

2i (4+5i)/(4-5i)(4+i)
8i-10/16+4i-20i+5

8i-10/21-16i
this puts the divisor in the middle


2i/(4+5i)(4-5i)(4+i)
=2i/41(4+i)
=2i/164+41i  

Probably the first one is what was asked for.