Question 972651
You started well but forced a step which changes part of the equation's meaning.


Go ahead and solve for x.  Use the fraction skills that you know.  When you get your answer or answerS, check each of them to see if it works in the original equation.  Notice that a value that you <b>must not accept</b> as any solution is x=3.  


I see a mistake in your step.


Clear the denominators by MULTIPLYING both members by the LCD, (x-3).  This gives,
{{{6(x-3)+4=3x(x-3)+1}}}
{{{6x-18+4=3x^2-9x+1}}}
and continue from this...