Question 972608
The numerator and the denominator of a certain fraction are consecutive odd numbers.
{{{n/((n+2))}}}
:
 If nine is subtracted from the numerator, then the ratio of the numerator to the denominator of the new fraction is two to three.
{{{((n-9))/((n+2))}}} = {{{2/3}}}
cross multiply
3(n-9) = 2(n+2)
3n - 27 = 2n + 4
3n - 2n = 4 + 27
n = 31
:
 Find the original fraction.
{{{31/33}}}
:
:
Check this, subtract 9 from the numerator, reduce fraction
{{{22/33}}} = {{{2/3}}}