Question 972559
7cos theta + 1 = 6sec theta 
Find, to the nearest degree, all values of theta in the interval 0 < theta < 360 which satisfy the equation. 
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7cosx+1=6secx
7cosx+1=6/cosx
lcd:cosx
7cos^2(x)+cosx=6
7cos^2(x)+cosx-6=0
(7cosx-6)(cosx+1)=0
..
7cosx-6=0
7cosx=6
cosx=6/7
x&#8776;31&#730;, 329&#730;
or
cosx+1=0
cosx=-1
x=180&#730;