Question 972537
( 3x^2. Over X^2-9 ) plus (X+2 over 4x-12) 
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(3x^2)/[(x-3)(x+3)] + (x+2)/(4(x-3))
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Least common denominator:: 4(x-3)(x+3)
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[4(3x^2-2)+(x+2)(x+3)]/[4(x-3)(x+3)]
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[12x^2 - 8 + x^2+5x+6]/[4(x-3)(x+3)]
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= [13x^2+5x-2]/[4(x-3)(x+3)]
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Cheers,
Stan H.
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