Question 972454
Let the numbers be A, B, and C.
{{{A+B+C=104}}}
.
.
{{{B=3C}}}
.
.
{{{C=A-9}}}
{{{A=C+9}}}
Substitute into first equation,
{{{(C+9)+3C+C=104}}}
{{{5C+9=104}}}
{{{5C=95}}}
{{{C=19}}}
Then,
{{{B=3(19)}}}
{{{B=57}}}
and
{{{A=19+9}}}
{{{A=28}}}