Question 972462
A number<pre>That's N</pre>is doubled,<pre>That's 2N</pre>and then seven is added.<pre>That's 2N + 7</pre>When the result is divided by forty,<pre>That's {{{(2N+7)/40}}}</pre>the quotient is two and the remainder is thirty-three.<pre>
That says {{{(2N+7)/40}}}{{{""=""}}}{{{2&33/40}}}

That's because you put the remainder over the divisor 
when you finish dividing. The divisor is 40 because that's
what we divided by.

We change the mixed number to an improper fraction {{{113/40}}}

Now we have this equation:

{{{(2N+7)/40}}}{{{""=""}}}{{{113/40}}}

We multiply both sides by 40, and get: 

2N + 7 = 113

We subtract 7 from both sides:

    2N = 106

We divide both sides by 2

    N = 53

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Now we check</pre>A number<pre>That's 53</pre>is doubled,<pre>That's 106</pre>and then seven is added.<pre>That's 106 + 7 = 113</pre>When the result is divided by forty,<pre>That's this division

  <u>   2</u>
40)113
    <u>80</u>
    33
</pre>the quotient is two and the remainder is thirty-three.<pre>It checks.

Edwin</pre>