Question 972417
If f'(x) = −7 x−3 and f(0) = −5, find f(x)
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Start by finding the "indefinite integral" of
f'(x) = −7 x−3
f(x) = (-7/2)x^2 - 3x + C
now we use f(0)=-5 to find C
-5 = (-7/2)(0)^2 - 3(0) + C
-5 = C
therefore:
f(x) = (-7/2)x^2 - 3x - 5