Question 972410
9y^2+77x-190=0..........equation 1
14x^2-9y^2-7x-6=0.......equation 2
9y^2=190-77x............equation 3
Substituting equation 1 in 2 we get
14x^2-9y^2-7x-6=0
14x^2-190+77x-7x-6=0
14x^2+70x-196=0
x^2+5x-14=0
x^2+7x-2x-14=0
x(x+7)-2(x+7)=0
(x-2)(x+7)=0
x=2
Substituting in equation 1 we get,
9y^2+154-190=0
9y^2=36
y^2=4
y=2
x=2 and y=2 is the solution.