Question 972381
Solve the following equations for 0 &#8804; (x) < 360
Sin^3(x)+sin^2(x)=0 
sin^2(x)+4sin(x)-5=0 
***
Sin^3(x)+sin^2(x)=0 
sin^2(x)(sinx+1)=0
..
sin^2(x)=0
sinx=0
x=0, 180&#730;
or
sinx+1=0
sinx=-1
x=270&#730;
..
sin^2(x)+4sin(x)-5=0 
(sinx+5)(sinx-1)=0
sinx=-5 (reject,(-1 < sinx < 1))
or
sinx=1
x=90&#730;
..
Note: I assumed you meant given domain is  0 &#8804; (x) < 360 instead of 0 < (x) < 360, otherwise, there is no solution to sinx=0, since 0 is not in the domain