Question 972368
{{{2x^2+3x-5=0}}} 

if you compare this to standard formula {{{ax^2+bx+c=0}}}, you see that {{{a=2}}}, {{{b=3}}}, and {{{c=-5}}} 

plug it in 

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

{{{x = (-3 +- sqrt( 3^2-4*2*(-5) ))/(2*2) }}} 

{{{x = (-3 +- sqrt( 9+40 ))/4 }}} 

{{{x = (-3 +- sqrt( 49 ))/4 }}} 

{{{x = (-3 +- 7)/4 }}}

solutions: 

{{{x = (-3 + 7)/4 }}}=>{{{x = 4/4 }}}=>{{{highlight(x =1)}}}

or

{{{x = (-3 - 7)/4 }}}=>{{{x = -10/4 }}}=>{{{highlight(x =-5/2)}}}


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(1,0,.12),circle(-5/2,0,.12),
locate(1,-0.3,p(1,0)),locate(-5/2,-0.3,p(-5/2,0)),
 graph( 600, 600, -10, 10, -10, 10, 2x^2+3x-5)) }}}