Question 972317
Let (-4,-1) be a point on the terminal side of an angle theta in standard position. Draw the angle then find the 6 trig ratios as well as the measure of angle theta. 
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x = -4
y = -1
r = sqrt[4^2 + 1^2] = sqrt(17)
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sin(t) = y/r = -1/sqrt(17)
cos(t) = x/r = -4/sqrt(17)
tan(t) = y/x = 1/4
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csc(t) = -sqrt(17)
sec(t) = -sqrt(17)/4
cot(t) = 4
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Cheers,
Stan H.
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