Question 972309
B; *
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Hypotenuse is 11, 1 leg is 9  ; 9^2 +a^2=11^2=121; 81+a^2=121;  a^2=40; a=2 *sqrt(10); (sqrt(40))=sqrt(10)*sqrt(4) 

ctn theta=adjacent/opposite  =2sqrt(10)/9