Question 972298
two times the square root of the sum of 3 consecutive even numbers is 24
<pre>
{{{2sqrt(n+(n+2)+(n+4))}}}{{{""=""}}}{{{24}}}

Divide both sides by 2

{{{sqrt(n+(n+2)+(n+4))}}}{{{""=""}}}{{{12}}}

Simplify under the radical:

{{{sqrt(n+n+2+n+4)}}}{{{""=""}}}{{{12}}}

{{{sqrt(3n+6)}}}{{{""=""}}}{{{12}}}

Square both sides:

{{{3n+6}}}{{{""=""}}}{{{144}}}

{{{3n}}}{{{""=""}}}{{{138}}}

{{{n}}}{{{""=""}}}{{{46}}}

The consecutive even integers are 46,48,50
Edwin</pre>