Question 972268
There are 6 combinations with 2 out of 4 eggs are defective.
{{{P=6(5/12)^2(7/12)^2}}}
{{{P=1225/3456}}}
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.
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Work it backwards, find the probability that none are defective.
{{{P(none)=(7/12)^4}}}
{{{P(none)=2401/20736}}}
So then,
{{{P=1-P(none)}}}
{{{P=20736/20736-2401/20736}}}
{{{P=18335/20736}}}