Question 970994
{{{y=x^2-2x-19}}}
{{{y=-4x+5}}}
So then,
{{{x^2-2x-19=-4x+5}}}
{{{x^2+2x-24=0}}}
{{{(x+6)(x-4)=0}}}
Two solutions:
{{{x+6=0}}}
{{{x=-6}}}
That's the given solution.
and,
{{{x-4=0}}}
{{{x=4}}}
So then,
{{{y=-4(4)+5}}}
{{{y=-16+5}}}
{{{y=-11}}}
(4,-11)
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