Question 972157
Maybe Marķa's kitchen was designed using SI measures, but she buys American tiles, and they measure those in inches.
We will need to convert units at some point.
You may have been given some conversion factors in class, or maybe you are expected to look them up.
I could look up how many square feet there are in a square meter, but that may be a conversion factor you are not expeted to use.
I know that 1 inch is 2.54 cm, and that 1 foot is 30.48cm, which is 0.3048m.
A tile that covers a square 1 ft by 1 ft (1 square foot), covers
{{{(0.3048m)(0.3048m) = 0.09290304m^2 = about 0.0929m^2}}} .
So, to cover {{{15m^2}}} with tiles such that each one covers {{{0.0929m^2}}} , you need
{{{15/0.0929=161.5 tiles}}} .
Of course, Marķa needs more than that, because cutting tiles to make them fit is a messy business,
and cut tiles break in unexpected, undesired ways.
Even if every cut was flawless, using only 161.5 tiles would cause some spaces on the corners and edges to be covered with many tiny pieces of tile.
I would figure out that along the 2.5 m length of the kitchen,
Marķa would lay a row of {{{6m/"0.3048 m"=19.7}}} tiles,
and that there would be {{{2.5m/"0.3048 m"=8.2}}} such rows across the width of the kitchen.
Allowing for 20 tiles (one to be cut) for each row,
and allowing for 9 rows (one row to be made of cut tiles) across the width of the kitchen,
I would calculate that Marķa should buy at least {{{20*9=180}}} tiles.