<PRE><B>Question 971859</B>
The ages of employees at a particular company have a mean of 39. 
The distribution of sample means for samples of size 200 is normal with a mean of 39 and a standard deviation of 0.79. 
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Suppose you take a sample of size 200 employees from the company and find that their mean age is 41.3. 
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How many standard deviations is the sample mean above the mean of the sampling distribution?2
z(41.3) = (41.3-39)/0.79 = 2.3/0.79 = 2.91
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Cheers,
Stan H.
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the answer is 2.9 please show work</PRE>