Question 971903
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Let x = smaller odd integer
Let x+2 = larger consecutive odd integer

two -fifth of <font color="red">the smaller</font> exceeds two -ninth of <font color="red">the greater</font> by 4

Replace <font color="red">the smaller</font> by (x)
Replace <font color="red">the greater</font> by (x+2)
We get

two -fifth of <font color="red">(x)</font> exceeds two -ninth of <font color="red">(x+2)</font> by 4

Recolor:

<pre>
<font color="red">two -fifth of</font> (x) exceeds <font color="red">two -ninth of</font> (x+2) by 4

Replace <font color="red">two- fifth of</font> by {{{red(expr(2/5)*"")}}}
Replace <font color="red">two- ninth of</font> by {{{red(expr(2/9)*"")}}}

We get
{{{red(expr(2/5)*"")}}}(x) exceeds {{{red(expr(2/9)*"")}}}(x+2) by 4

Recolor:
{{{expr(2/5)*"")}}}(x) <font color="red">exceeds</font> {{{expr(2/9)*"")}}}(x+2) <font color="red">by</font> 4

Replace <font color="red">exceeds...by</font> by <font color="red">=...+</font>
We get:

{{{expr(2/5)*"")}}}(x) <font color="red">=</font> {{{expr(2/9)*"")}}}(x+2) <font color="red">+</font> 4

Multiply through by LCD = 45 to remove fractions:

{{{45*expr(2/5)*"")}}}(x) = {{{45*expr(2/9)*"")}}}(x+2) + 45*4

18(x) = 10(x+2)+180

You finish:

Edwin</pre>