Question 971582
Find the value sin2 x on the interval (3pi/2, 2pi) given tan x = -3
tanx=-3/1
hypotenuse of reference right triangle=&#8730;(-3)^2+1=&#8730;10
sinx=-3/&#8730;10
cosx=1/&#8730;10
sin(2x)=2sinxcosx=2*(-3/&#8730;10)(1/&#8730;10)=-6/10=-3/5