Question 971862
x^2-16x-45/x^2-3x-18 + x^2-2x-27/x^2-3x-18

My snag is, I can't figure out how to factor the first numerator because I don"t see any terms that make the product -45 = to the sum of -16.
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You're right, it can't be factored.
The DENs are the same, so add them.
= {{{(2x^2 - 18x - 72)/((x+3)*(x-6))}}}
= {{{2(x^2 - 9x - 36)/((x+3)*(x-6))}}}
= {{{2(x+3)*(x - 12)/((x+3)*(x-6))}}}
= {{{2(x - 12)/(x-6))}}}