Question 971713
Using the equation of motion,
{{{v=u-g*t}}}  (where symbols have usual meanings)
From above equation, we get,
{{{0=30-32*t}}} (At max height, velocity =0 and taking g= 32feet/second^2 approx.)
=> {{{t= 30/32}}}
So, it will take 30/32 seconds(i.e less than 1 second to reach maximum height, and then ball starts descending. So, after 1 sec, ball is below its maximum height and  in downward motion.