Question 971596
(x+4)*(x+4) = x^2 + 8x + 16


(x-4)*(x-4) = x^2 - 8x + 16


i believe the factors needed to be (x-4) * (x-4) because, when you solve for x, you then get x = 4.


(x-4)*(x-4) = 0


set each of the factors equal to 0 to get:


x-4 = 0
x-4 = 0


solve for x to get:


x = 4
x = 4


if x = 4, then the factor has to be x-4 because x-4 = 0


when you have the solution and you want to convert it into a factor, you have to set the equation equal to 0.


start with x = 4
subtract 4 from both sides of the equation to get x - 4 = 0
that's your factor.