Question 971543
<pre>
Instead of doing it for you, I'll just tell you how so you
can do it yourself:

{{{system(2/x-2/y+1/z=-1,4/x+1/y-2/z=-9,1/x+1/y-3/z=-9)}}}

Let {{{u=1/x}}}, {{{v=1/y}}}, {{{w=1/z}}}

Then the system will not have variables in the denominator,
for the system will be:

{{{system(2u-2v+w=-1,4u+v-2w=-9,u+v-3w=-9)}}}

You can solve that and get the values for u, v, and w,

Then substitute those values for u,v, and w into

{{{u=1/x}}}, {{{v=1/y}}}, {{{w=1/z}}}

and them to find x, y, and z.

Edwin</pre>