Question 971505
Can you help me multiply this quadratic equation? 
121-x^2/x^2-22x+120 times x^2-24x+140/x^2-18x+77 
I would set up the 1st equation like this:
Numerator:: 121-x^2/x^2-22x+120 =(11+x)(11-x)/(x-12)(x-10) 
and
Denominator:(x^2-24x+140)/(x^2-18x+77) = (x-10)(x-14)/(x-11)(x-7)
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Multiply to get:
[(11+x)(11-x)/(x-12)(x-10)]*[(x-10)(x-14)/(x-11)(x-7)]
Cancel factors common to numerator and denominator to get:
[11+x))/(x-12)]*[(x-14)/(-1)(x-7)]
After I did the equations but my answer differed from the answer key.
My answer is:
-(x+11)(x-14)/(x-12)(x-7)
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Cheers,
Stan H.
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