Question 971464
 log (x^2+x-6)^2 to base x+1 = 4
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{{{log((x+1),(x^2+x-6)^2) = 4}}}
--> {{{(x+1)^4 = (x^2+x-6)^2}}}
{{{(x+1)^2 = (x^2+x-6)}}}
{{{x^2 + 2x + 1) = x^2+x-6}}}
2x+1 = x-6
x = -7 --> base -6, not allowed
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{{{(x+1)^2 = -(x^2+x-6)}}}
{{{x^2 + 2x + 1) = -x^2 - x + 6}}}
{{{2x^2 + 3x - 5 = 0}}}
(2x + 5)*(x - 1) = 0
x = 1 --> log(-4) not allowed
x = -5/2 --> base -1.5 not allowed